Question 767672
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Your work:


f(x)=6/x+7


y=6/x+7


y=7x+6/x 


xy-7x=6
  

x(y-7)=6
 

*[tex \LARGE x\ =\ \frac{6}{y\ -\ 7}]


*[tex \LARGE f(y)\ =\ \frac{6}{y\ -\ 7}]


*[tex \LARGE f^{-1}(x)\ =\ \frac{6}{x\ -\ 7}]


Yes, that is correct if the actual starting function was *[tex \LARGE f(x)\ =\ \frac{6}{x}\ +\ 7].  However, if the original function was really *[tex \LARGE f(x)\ =\ \frac{6}{x\ +\ 7}], that is a horse of a completly different color.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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