<PRE><B>Question 767678</B>
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*[tex \LARGE y] varies directly with *[tex \LARGE x] means *[tex \LARGE y\ =\ kx].


So if *[tex \LARGE y\ =\ 3] when *[tex \LARGE x\ =\ 2], solve *[tex \LARGE 3\ =\ 2k] for *[tex \LARGE k]


Then using what you now know the value of *[tex \LARGE k] to be, solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 6k]


for *[tex \LARGE y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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