<PRE><B>Question 66033</B>
simplify 
6 - 7 times the square root of 3 
DIVIDED BY 
2 times the square root of 3 + 4

(6-7sqrt3)/(4+2sqrt3) 

First, multiply both numerator and denominator by(4-2sqrt3), the conjugate of (4+2sqrt3).  This will get rid of the radical in the denominator.

NUMERATOR: (6-7sqrt3)(4-2sqrt3)=24-28sqrt3-12sqrt3+(14)(3)=66-40sqrt3
DENOMINATOR(4+2sqrt3)/(4-2sqrt3)=16+8sqrt3-8sqrt3-(4)(3)=16-12=4

Now we have
(66-40sqrt3)/4 divide numerator and denominator by 2 and we get:

(33-20sqrt3)/2

Hope this helps----ptaylor

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