Question 767423
Of the {{{50}}} deer re-captured, {{{30}}} had tags.
That means that {{{30/50=3/5=0.6}}}=60% of the re-captured deer had tags.
 
Assuming the same proportion of the entire deer population has tags, the {{{320}}} deer initially tagged and released would be {{{3/5}}} of the total number of deer.
 
If the entire deer population consists of {{{x}}} deer,
{{{3/5=320/x}}} --> {{{3x=320*5}}} --> {{{x=320*5/3}}}
That calculates as {{{320*5/3=1600/3=533&1/3}}}.
So the biologist will estimate it as {{{x=533}}}