Question 767511
A motorboat travels 756 mi in 9 hours going upstream and 684 mi in 6 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
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Upstream DATA:
distance = 756 miles ; time = 9 hrs ; rate = 756/9 = 84 mph
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Downstream DATA:
distance = 684 miles ; time = 6 hrs ; rate = 684/6 = 114 mph
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Equations:
b - c = 84
b + c = 114
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2b = 198
b = 99 mph (speed of the boat in still water)
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Solve for "c":
b +c = 114
99 + c = 114
c = 15 mph (speed of the current)
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Cheers,
Stan H.