Question 66039
QUESTION:


one number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Find both numbers


ANSWER:

Here it is given that one number is 4 less than 3 times a second number.


So lets take  the second number as x.


3 times a second number= 3x

4 less than 3 times a second number = 3x - 4



Then we have first number is 4 less than 3 times a second number 

That is first number is 3x-4


Now twice the first number = 2(3x-4)


Again 3 more than twice the first number = 2(3x -4)+ 3


Now...3 more than twice the first number is decreased by the second(that is x)

is equal to 11


==> 2(3x -4)+ 3 - x = 11


Remove the parenthesis...


==> 2* 3x - 2*4 + 3 - x = 11


==> 6x - 8 + 3 - x = 11


==> 5x  -5 = 11


Add 5 on both sides...


==> 5x - 5 + 5 = 11 + 5



==> 5x = 16


Divide by 5 on both sides...


==> 5x/5 = 16/5


==> x = 16/5



Now substitute this value in  3x-4


==> first number = 3*16/5 - 4


==> 48/5 -4


==> 48/5 -4*5/5


==> (48 - 20)/5


==> 28/5



So the numbers are 16/5 and 28/5



Hope you understood...


Regards..


praseena.