Question 767062
If 1/6 of a solution of alcohol is replaced by water alone, the resulting mixture becomes a 30% solution. What is the percentage of alcohol in the original solution?
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let x=percentage of alcohol in the original solution?
let t=amount of solution (does not change)
x*(5/6)t+0%*(1/6)t=30%t
5x/6+0=.30
5x=1.8
x=.36
percentage of alcohol in the original solution=36%