Question 767212
In 2 hrs, the walker has a head start of
{{{ d[1] = 3*2 }}}
{{{ d[1] = 6 }}} mi
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Start a stopwatch when the jogger leaves,
let {{{ t }}} = the time in hrs on the stopwatch when
the jogger catches the walker
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Let {{{ d }}} = the distance the jogger travels in miles
when the jogger catches the walker
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Walker:
(1) {{{ d - 6 = 3t }}}
Jogger:
(2) {{{ d = 8t }}}
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Substitute (2) into (1)
(1) {{{ 8t - 6 = 3t }}}
(1) {{{ 5t = 6 }}}
(1) {{{ t = 6/5 }}}
(1) {{{ t = 1.2 }}}
and {{{ .2*60 = 12 }}}
It will take the jogger 1 hr and 12 min to catch the walker
check:
(1) {{{ d - 6 = 3*1.2 }}}
(1) {{{ d = 6 + 3.6 }}}
(1) {{{ d = 9.6 }}} mi
and
(2) {{{ d = 8t }}}
(2) {{{ d = 8*1.2 }}}
(2) {{{ d = 9.6 }}} mi
OK