Question 767092
If you need the logarithm to the base 10

log10 (6.023*10^23) = log10(6.023) + log10(10^23)  ---> since log(a*b)= log a + log b

= log10(6.023) + 23 ---->by the definition of logarithm, logx(x^a) = a

log10(6.023) = 0.7798 (from calculator)

So log10 (6.023*10^23) = 23.7798

:)