Question 766973
Graph:
y=(x+4)^2+3
by using techniques of "transformations".
.
Starting point:
y = x^2
This is simply a parabola that opens upwards and the vertex is at the origin.
.
y = (x+4)^2
The above "horizontally shifts" the "starting point" to the LEFT 4 units.  That is, the vertex is now at (-4,0).
.
Finally,
y = (x+4)^2 + 3
Shifts it vertically UP three units.  That is, the vertex is now at (-4,3).