Question 766811
c)(i) Write the quadratic expression {{{x^2-34x+9}}} in completed square form

*[invoke completing_the_square 1, -34, 9]

(ii) use the completed square form from part (c) (i) to solve the equation {{{x^2-34x+9=0}}}, leaving your answer in exact (surd) form

{{{(x-17)^2-280 = 0}}}

(iii) use the completed square form from part (c)(i)to write down the vertex of the parabola {{{y=x^2-34x+9}}}

{{{y=(x-17)^2-280 }}}....compare to {{{y=(x-h)^2+k}}} and you will see that {{{h=17}}} and {{{k=-280}}} which means

the vertex of the parabola is at ({{{17}}},{{{-280}}}


since the graph above is not good, I will make another one for you to see it is a parabola:


{{{ graph( 600, 600, -50, 50, -330, 50,(x-17)^2-280 ) }}}