Question 766707
They meet when the sum of their walked distances equals 1150m.
Their time spent walking is the same because they begin their walks toward each other at the time starting time, and keep walking until meeting.  Call this time, x.


Person_________speed_________time_________distance
Ann____________2/3___________(_x_)________(___)
Yohan__________1.25__________(_x_)________(___)
Total_____________________________________1150


The two expressions for the unknown distances are based on r*t=d using r for rate, t for time, d for distance.  



Person_________speed_________time_________distance
Ann____________2/3___________(_x_)________((2/3)x)
Yohan__________1.25__________(_x_)________(1.25x)
Total_____________________________________1150


We can first find the time, x, in seconds using sum of the distances equation:
{{{(2/3)x+(1&1/4)x=1150}}}

{{{(2/3)x+(5/4)x=1150}}}
{{{(8/12+15/12)x=1150}}}
{{{(23/12)x=1150}}}
{{{x=1150*12/23}}}
{{{x=50*12}}}
{{{highlight(x=600)}}} seconds
This is also 10 minutes.______{{{highlight(x=600/60=10)}}} minutes.


COMPUTING DISTANCES:
Ann walked {{{(2/3)*600=400}}} meters
Simply by difference, Yohan walked {{{1150-400=750}}} meters