<PRE><B>Question 766684</B>
 two air planes leave at the same time traveling in the same direction. At six hours they are 1530 miles apart. 1st plane is 4 times faster than the 2nd plane. I am to find how fast each plane is going.
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Slower plane DATA:
rate = x mph ; time = 6 hrs ; distance = r*t = 6x miles
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Faster plane DATA:
rate = 4x mph ; time = 6 hrs ; distance = r*t = 24x miles
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Equation:
faster distance - slower distance = 1530 miles
24x  - 6x = 1530
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18x = 1530
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x = 85 mph (slower plane speed)
4x = 340 mph (faster plane speed)
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Cheers,
Stan H.</PRE>