Question 766567
The ratio of the ages of A and B ten years ago was 3:5.
 If the ratio of their present ages is 2:3
 how old is B today?
:
Let x = the multiplier
then
2x = age of A
3x = age of B
:
{{{(2x-10)/(3x-10)}}} = {{{3/5}}}
cross multiply
5(2x-10) = 3(3x-10)
10x-50 = 9x-30
10x - 9x = -30 + 50
x = 20 is the multiplier
: 
3*20 = 60 is B's age