Question 65958
We first calculate the average velocity of both the buses.


That is given by: 



Average Velocity = {{{(44 + 48)/2}}} 


                 = 46 milies/ hr 



Therefore, total time taken to cover 274 miless by the two buses would be 


                = {{{Distance/Speed}}} 



                = {{{274/46}}} 



                = 5.95 hrs 



Then there is a time gap of 1 hr for the 2nd bus to start from the initial position


Therefore, 


5.95 + 1 = 6.95 hrs



Hence, the solution.