Question 766262
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z^2\ -\ iz\ +\ 2\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{1,2}\ =\ \frac{i\ \pm\ \sqrt{-1\ -\ 4(1)(2)}}{2(1)}] 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{1,2}\ =\ \frac{i\ \pm\ \sqrt{-1\ -\ 8}}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{1,2}\ =\ \frac{i\ \pm\ i\sqrt{9}}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{1,2}\ =\ \frac{i\ \pm\ 3i}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{1}\ =\ \frac{4i}{2}\ =\ 2i]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z_{2}\ =\ \frac{2i}{2}\ =\ i]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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