Question 766122
Highly believing that 'a' will not be affected, an attempt at guessing is tried, not really the best approach:

ax^2+2b+2c=0
roots be {{{ x=(-2b+- 2*sqrt(b^2-a*2*c))/(2a)}}}
But seems to fail.  Looking as 4c as replacement for c will be better, try:


{{{ax^2+2b+4c=0}}}
{{{x=(-2b+- sqrt(4b^2-4*a*4c))/(2a)}}}
{{{x=(-2b+- 2*sqrt(b^2-4ac))/(2a)}}}
{{{x=(-b+- sqrt(b^2-4ac))/a}}}, yes, this root pair is twice what we normally have in our solution formula.


COMPARE:

{{{ax^2+bx+c=0}}}
{{{x=(-b+- sqrt(b^2-4ac))/(2a)}}}

versus

{{{ax^2+2b+4c=0}}}
{{{x=(-b+- sqrt(b^2-4ac))/(a)}}}