Question 766096
let them meet after distance x km

let time taken by first jogger be t
distance = x
speed = 8kmph

x= 8*t 

time taken by jogger II = t-5 hours
distance = x km
speed = 10 kmph

x= 10(t-5/60)

8t= 10(t-1/12)multiply equation by 12

96t=120t-10

24t= 10
t=10/24 
t=5/12

t= 5/12 hours
5/12 * 60 = 25 minutes

the Jogger II will catch up after 25-5 = 20 minutes