<PRE><B>Question 766023</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\,-\,h\right)^2\ +\ \left(y\,-\,k\right)^2\ =\ r^2]


is the equation of a circle centered at *[tex \LARGE\ \left(h,\,k\right)] and radius *[tex \LARGE r].  Recalling that the radius is one-half of the diameter, just substitute the values.  Hint:  for the *[tex \LARGE x] part, minus a minus is a plus.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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