<PRE><B>Question 766014</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{y}\ =\ \frac{7}{3}]


Hence


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ =\ \frac{7y}{3}]


Substitute into


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ y^2\ =\ 232]


Then solve the quadratic for  *[tex \LARGE y].  Don&#39;t forget:  Quadratics have two roots.  Then substitue the *[tex \LARGE y] values back into  *[tex \LARGE  x\ =\ \frac{7y}{3}] and calculate *[tex \LARGE x]
 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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