Question 765967
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The probability that the first number is less than 8 is given by 8 successes diveded by ten possibilities.


Then, given that the first number was less than 8, there are then 7 successes out of 9 possibilities since this is a without replacement experiment.


Then 6 of 8, and so on.


The overall probability is the product of the probabilities:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{8}{10}\ \times\ \frac{7}{9}\ \times\ \frac{6}{8}\ \times\ \frac{5}{7}\ \times\ \frac{4}{6}]


You can do your own arithmetic.  Hint:  If you do enough cancelling, you don't have to do ANY multiplying.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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