Question 765808
how many gallons of a 90 antifreeze solution must be mixed with 100 gallons of 25 antifreeze to get a mixture that is 80% antifreeze
---------
Equation::
0.90x + 0.25*100 = 0.80(x+100)
--------
90x + 25*100 = 80x + 80*100
10x = 55*100
x = 550 gallons (amt. of 90% solution needed)
=======================================
Cheers,
Stan H.
===================





you need ___ gallons?
-------