Question 765794
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If Belle can see all 5 odd numbers and only 3 of the 5 odd numbers appear in Andy and Carol's hands, the other two odd numbers, namely 3 and 9, must be in your own hand.


Since Andy can see two hands that total the same, Belle's hand totals 16, and Carol's hand totals 12, your hand must total either 16 or 12.  But since you know that you have a 3 and a 9 which total 12 by themselves, you know that your total cannot be twelve because there is no zero card. Therefore your total must be 16 and your cards must be 3, 4, and 9.


If you want a paper written, I'm not doing that for free.  Write back and I'll give you a quote for a full up scholarly paper.  


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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