Question 65865
{{{1/(x+5y)-5/(x-5y)+3/(x^2-25y^2)}}}
:
We factor the 3rd denominator and that will be the common denominator, we have:
{{{1/(x+5y)-5/(x-5y)+3/((x-5y)(x+5y))}}}
:
{{{(1(x-5y) - 5(x+5y) + 3)/(x-5y)(x+5y))}}}
:
{{{(x - 5y - 5x - 25y + 3)/((x-5y)(x+5y))}}}
:
{{{(-4x - 30y + 3)/(x-5y)(x+5y))}}}; That's about all you can do with it