Question 765488
The given zeros mean you have this function:


{{{f(x)=k(x-3)(x-2)(x+1)}}}


Using x=0 allows you to find k.
{{{f(0)=k(-3)(-2)(1)=18}}}
{{{k*6=18}}}
{{{k=3}}}


Result:  {{{highlight(f(x)=3(x-3)(x-2)(x+1))}}}