Question 765566

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(5,-8\right)]. So this means that {{{x[1]=5}}} and {{{y[1]=-8}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-2,-11\right)].  So this means that {{{x[2]=-2}}} and {{{y[2]=-11}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-11--8)/(-2-5)}}} Plug in {{{y[2]=-11}}}, {{{y[1]=-8}}}, {{{x[2]=-2}}}, and {{{x[1]=5}}}



{{{m=(-3)/(-2-5)}}} Subtract {{{-8}}} from {{{-11}}} to get {{{-3}}}



{{{m=(-3)/(-7)}}} Subtract {{{5}}} from {{{-2}}} to get {{{-7}}}



{{{m=3/7}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(5,-8\right)] and *[Tex \LARGE \left(-2,-11\right)] is {{{m=3/7}}}