Question 765451
 {{{-3x^2+6x}}} has maximum; as you can see coefficient in front of{{{x^2}}} is negative number {{{-3}}} and it means parabola opens downward and vertex is maximal point


{{{y=-3x^2+6x}}}..to find the x-coordinate of the vertex, use {{{-b/2a}}}

since {{{a=-3}}} and {{{b=6}}}, we will have {{{-b/2a=-6/(-3*2)=1}}}

the x-coordinate of the vertex is {{{1}}}

then find the y-coordinate that goes with it by using that value for {{{x}}} in our equation for {{{y=-3x^2+6x}}}

{{{y=-3*1^2+6*1}}}

{{{y=-3+6}}}

{{{y=3}}}

so, the vertex is at ({{{1}}},{{{3}}})


{{{ graph(600, 600, -10,10, -10, 10, -3x^2+6x) }}}