Question 765449
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If the lead coefficient is positive, the parabola opens upward and the vertex is a minimum, otherwise the parabola opens downward and the vertex is a maximum.


The *[tex \LARGE x]-coordinate of the vertex of the quadratic polynomial function *[tex \LARGE p(x)\ =\ ax^2\ +\ bx\ +\ c] is found using the formula *[tex \LARGE x_v\ =\ \frac{-b}{2a}].  The *[tex \LARGE y]-coordinate of the vertex, and either the minimum or maximum value of the function depending on which way the parabola opens, is the value of the function at *[tex \LARGE x_v].  Which is to say:  *[tex \LARGE y_v\ =\ p(x_v)\ =\ a(x_v)^2\ +\ bx_v\ +\ c]


The only thing left for you to do is some arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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