<PRE><B>Question 765418</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 1\ =\ \sqrt{2x\ -\ 6}]


Square both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 2x\ +\ 1\ =\ 2x\ -\ 6]


Collect terms to standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ +\ 7\ =\ 0]


Use the quadratic formula.  Note:  *[tex \LARGE 16\ -\ 28\ &lt;\ 0], therefore you have a conjugate pair of complex roots.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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