Question 765260
two people working together can do a job in 6 hours. if one of them works twice as fast as the other. How long would it take the faster person, working alone, to finish the same job?
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together rate::: 1/6 job/hr.
slower person rate: 1/(2x) job/hr.
faster person rate: 1/x job/hr.
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Equation:
rate + rate = together rate
1/x + 1/(2x) = 1/6
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Multiply thru by 6x:::
6 + 3 = x
x = 9 hrs (time for the slower person to do the job alone)
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Cheers,
Stan H.
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