Question 765217
A bag contains 5 red balls, numbered one through five, and 6 blue balls, numbered one through six. What is the probability that a ball chosen in random is a one or blue?
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P(one or blue) = P(one) + P(blue) - P(one AND blue)
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P(one or blue) = 2/11 + 6/11 - 1/11 = 7/11
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Cheer
Stan H.
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