Question 8457
{{{8x + 15/x = 29}}}... a fractional term, so multiply all 3 terms by x, to give


{{{8x^2 + 15 = 29x}}}
--> {{{8x^2 -29x + 15 = 0}}}


This is a quadratic that you can factorise as (8x-5)(x-3) = 0


so either 8x-5 = 0 OR x-3 = 0


so x = 5/8 OR x = 3


jon