Question 764883
ur no. is 975 
let be first no. be (x)
therefore three consecutive no. are x, x+1, x+2
so the sum of these no. are 
x+x+1+x+2=975
3x+3=975
3x=975-3
3x=972
x=972/3
x=324
therefore no. are 324,325,326