Question 764823
The other needed zero is 3-9i, because complex zeros come in conjugate pairs.


Your function in a form other than general (here being factored) will be 
{{{p(x)=(x-8)(x+14)(x-(3+9i))(x-(3-9i))}}}


You asked for "real coefficients" and in "standard form".  In keeping with that, you probably want the quadratic factor corresponding to the two complex factors containing imaginary components.  


{{{(x-3-9i)(x-3+9i)=(x-3)^2-(9i)^2=x^2-6x+9+81=x^2-6x+90}}}

Finally without showing any complex numbers plainly, your standard form function if other than general form, is {{{highlight(p(x)=(x-8)(x+14)(x^2-6x+90))}}}