Question 764699
Find the dimensions of the rectangle that has a length 3 meters more than its width and a perimeter equal in value to its area? 
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width = w
length = w+3
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Perimeter = 2(width+length) = 2(w+w+3) = 4w+6
Area = width*length = w(w+3) = w^2+3w
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Equation:
Perimeter = Area
w^2 + 3w = 4w+6
w^2 - w -6 = 0
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Factor:
(w-3)(w+2) = 0
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Positive Solution:
width = w = 3
length = w+3 = 6
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Cheers,
Stan H.