Question 764673
{amount of pure acid}/{amount of solution}={concentration of adjusted solution}


L = 25%, concentration of available acid solution
T = 40% acid
R = 600, the volume ml. of available solution
v = ml. volume of 100% acid to add to get T as result.  UNKNOWN.


{{{(L*R+100*v)/(R+v)=T}}}
Solve for v.