Question 764660


let' two positive numbers be {{{x}}} (larger) and {{{y}}} (smaller)

if a difference is {{{8}}}, then {{{x-y=8}}}......eq.1

if the larger number is twice the smaller minus {{{7}}}, then  {{{x=2y-7}}}.....eq.2

now solve the system:

{{{x-y=8}}}......eq.1
{{{x=2y-7}}}.....eq.2
___________________________substitute {{{x}}} from 2 in 1


{{{2y-7-y=8}}}......eq.1....solve for {{{y}}}

{{{y=8+7}}}

{{{y=15}}}

now find {{{x}}}

{{{x=2*15-7}}}.....eq.2

{{{x=30-7}}}

{{{x=23}}}


so, two positive numbers are: {{{23}}} and {{{15}}}