Question 764521
first factor out the x and we get
x(x^3-4x^2-7x+28) = 0
The Rational Root Theorem says we must factor the x^3 coefficient and 28
The x^3 coefficient is 1 so its factors are + or minus 1, so q could= +or-1
The factors of 28 are 1,2,4,7,28, so p could = +or-1, +or-2, +or-4, +or-7, +or-28
so p/q = +or-1/1, +or-2/1, +or-4/1, +or-7/1, +or-28/1