Question 65817
x^2+4x+4=7
x^2+4x+4-7=0
x^2+4x-3=0 using the quadratic equation we get
x=(-b+-sqrt[b^2-4ac])/2a
x=(-4+-sqrt4^2-4*1*-3])/2*1
x=(-4+-sqrt16+12])/2
x=(-4+-sqrt28)/2
x=(-4+-5.29)/2
x=(-4+5.29)/2
x=-1.29/2
x=.645 solution
x=(-4-5.29)/2
x=-9.29/2
x=-4.645 solution
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