Question 65808
Solve by using the quadratic formula 
2x = 3x^2 - 3
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Rewrite as 3x^2-2x-3=0
a=3, b=-2, c=-3
x=[2+-sqrt(4-4*3*-3)]/(2*3)
x=[2+-2sqrt(10)]/6
x=[1+-sqrt10)]/3
x=(1/3)+(1/3)sqrt(10) or x=(1/3)-(1/3)sqrt(10)
Cheers,
Stan H.