Question 764344
The probability of getting a ticket at least once is 1 - the probability of never getting a ticket.<P>
The probability of not getting a ticket at each light is .9 (1 - probability of a ticket.)  The sum of probabilities of n independent events (if each event probability is A) A^n.<P>
The probability of not getting a ticket at five lights is .9^5.<P>
The probability of getting at least one ticket is 1-.9^5 = 1-.59049 = .40951= approximately .410.