<PRE><B>Question 764344</B>
If you run a red traffic light at an intersection, there is a .10 probability tha tyou will be given a traffic violation. If you runa red traffic light at this intersection five different times, what is the probability of getting at least one traffic violation? 
I know the answer is .410, but please explain the process.
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These are independent events.
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Binomial Problem with n = 5 and p(violation) = 0.10 ; P(no vio) = 0.9
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P(at least one in five) = 1 - P(no vios in five) = 1-(0.9)^5 = 0.4095
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Cheers,
Stan H.
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