Question 764144
 a survey of 120 executives found that 80 own luxury cars,50 own SUV's and 38 own both.
# with no lux = 120-80 = 40
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A.) find the probability that an executive owns either a luxury car or an SUV 
P(lux OR SUV) = P(lux)+P(SUV)-P(lux AND SUV) = [80+50-38]/120 = 92/120
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B)find the probability that an executive owns an SUV given that he doesn't own a luxury car
P(SUV | no lux) = [P(SUV AND no lux)]/P[lux] = 50/80 = 5/8
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Cheers,
Stan H.
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