Question 764051
Your question equation was adjusted according to ability to match at least one of your choices.

Squaring both sides and dividing by 12, you get: {{{3x^2=2+x}}},
{{{3x^2-x-2=0}}}
using general solution to quadratic formula,

{{{x=(1+- sqrt(1-4*3*(-2)))/6}}}
{{{x=-2/3}}} or {{{x=1}}}




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Your originally given equation would properly be written in text and tags, this way:
6x=sqrt(24+12x)
and then using triple closing brackets on the right side and triple opening brackets on the left side,

{{{6x=sqrt(24+12x)}}}