Question 764112
if an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time is given by: 
h=-16t^2+vt+s (where h and s are in ft, t is in seconds, and v is in ft/sec)
if a rock is thrown upward from a height of 100ft, with an initial velocity of 32ft/sec, solve for the time that it takes for it to hit the ground. (when h=0) 
answer in seconds. 
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h=-16t^2+vt+s
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h(t) = -16t^2 + 32t + 100
-16t^2 + 32t + 100 = 0
Solve for t
*[invoke solve_quadratic_equation -16,32,100]
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t =~ 3.6926 seconds
Ignore the negative solution