<PRE><B>Question 764092</B>
A container has 1 red marble 2 green marbles 3 yellow marbles and 4 orange marbles. You select 2 marbles without replacement. 
Find:
---Probability of selecting 2 orange marbles = 4C2/10C2 = 6/45 = 2/15
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--Probability of selecting 2 red marbles = 0/45 = 0
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--Probability of selecting atleast 1 red marble:::
 1 - 9C2/10C2 = 1-36/45 = 9/45 = 1/5
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---Probability that the second marble is yellow given the first marble is green.
= P(yellow AND green)/P(green) = [(3*2)/10C2]/[2/10] = (6/45)/(1/5) = 2/3
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Cheers,
Stan H.
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