<PRE><B>Question 764074</B>
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That&#39;s right...there is no real solution. That means that the zeros are complex numbers rather than real numbers.  Complex numbers are of the form *[tex \LARGE a\ +\ bi] where *[tex \LARGE a] and *[tex \LARGE b] are real numbers and *[tex \LARGE i] is the imaginary number defined by *[tex \LARGE i^2\ =\ -1]. You also need to check your arithmetic.


So *[tex \LARGE \ \ \ \ \ \ \ \ x_{1,2}\ =\ \frac{1\ \pm\ \sqrt{1\ -\ 16}}{4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ x_{1,2}\ =\ \frac{1}{4}\ \pm\ \frac{i\sqrt{15}}{4}] 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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