Question 764032
The sum of two numbers is 41. 
One number is one less than twice the other. 
Find the larger of the two numbers.
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Equations:
a + b = 41
a = 2b -1
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Substitute for "a" and solve for "b"
2b-1 + b = 41
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3b = 42
b = 14
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Solve for "a":
a = 2b-1
a = 2*14-1 = 27
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Cheers,
Stan H.
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