Question 763797

let a number be {{{x}}}

 the sum of a number and {{{4}}}: {{{x+4}}}

 is subtracted from {{{20}}}: {{{20-(x+4)}}}

the result is {{{3}}} times the number: {{{20-(x+4)=3x}}} 

{{{20-(x+4)=3x}}}....solve for {{{x}}}

{{{20-x-4=3x}}}

{{{20-4=3x+x}}}

{{{16=4x}}}

{{{16/4=x}}}

{{{highlight(4=x)}}}