Question 763776
From {{{0}}} to {{{4}}} means {{{p = 4}}}

now use a form: {{{(x-h)^2 = 4p(y-k)}}}......you have {{{h = 0}}}, {{{k = 0}}}, {{{p = 4}}}

Substitute the values:

{{{(x-0)^2 = 4*4(y-0)}}}

{{{16y = x^2}}}

{{{y = (1/16)x^2}}}


 {{{ graph( 600, 600, -10, 10, -10, 10, (1/16)x^2) }}}